what is the delta H of N2 + 3H2 ---> 2NH3 + 22,000 cal

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1. The following standard free energies are given for 25 degrees celcius.1) N2(g) + 3H2(g)-> 2NH3(g) delta g = -33.0 kJ 2) 4NH3(g)
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2. N2 + 3H2 --> 2NH3At 25°C (delta)Ho = -92.22 kJ and (delta)So = -198.53 J/K. Using this information, calculate the equilibrium
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3. N2 + 3H2 --> 2NH3At 25°C (delta)Ho = -92.22 kJ and (delta)So = -198.53 J/K. Using this information, calculate the equilibrium
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4. The following reactions are important ones in catalytic converters in automobiles. Calculate Delta G for each at 298 K. Predict
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