So AC = 5
tan 37° = 5/BC
BC = 5/tan37 = ...
sin 37° = 5/AB
AB = 5/sin 37° = ....
b) you were given angle ABC = 37 , so it is found
the other angle would be 53°
In a right tringle,/_ABC has a value of 37 degree while its opposite side is equal to 5,where angle c=90 degree
find:
a.) Remaining sides of the triangle
b.) /_ABC using any trigonometry functions
1 answer
1 answer