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Asked by Anonymous

Write the expression in terms of common logarithms, and then give a calculator approximation (correct to four decimal places).
log_(9) \(77\) =
14 years ago

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Answered by Reiny
I don't understand your notation.

Did you mean log<sub>9</sub> 77 ??

If so, then this would be
log 77/log9 = appr. 1.976951 or
1.9770 correct to 4 decimals
14 years ago

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