Asked by Neha

2NaF + CaCl2 ¨ CaF2 + 2NaCl
An excess of 0.20 M NaF is used to precipitate the calcium ions from a
50.0 mL sample of a calcium chloride solution. What is the concentration
of the original calcium chloride solution?

Answers

Answered by DrBob222
Ya gotta have more info, like the mass of the CaF2 pptd.
Answered by Neha
In regards to DrBob222, there were 3 parts to this question; the first part said there were .1952 g and the mols were 2.504 * 10^-3 mol. But I don't know if this part refers to the first part because it doesn't sound like it does.
Answered by DrBob222
0.1952 g CaCl2/molar mass CaF2 = 0.002504 mole CaF2. Convert that to moles CaCl2 which is 0.002504.
Then concn CaCl2 = mole CaCl2/L soln = ? 0.002504/0.050 L = ??M
Answered by Neha
Thanks!
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