Asked by ABCD
                How many molecules of oxygen are produced from the decomposition of 8.75 g of hydrogen peroxide in the following equation Mg + H2O2 -->  MgH2 + O2
options:
	
8.75 x 1024
	
6.02 x 1023
	
1.55 x 1022
	
5.27 x 1024
	
1.55 x 1023
            
            
        options:
8.75 x 1024
6.02 x 1023
1.55 x 1022
5.27 x 1024
1.55 x 1023
Answers
                    Answered by
            DrBob222
            
    Here is a worked example of a stoichiometry problem. Just follow the steps. 
http://www.jiskha.com/science/chemistry/stoichiometry.html
    
http://www.jiskha.com/science/chemistry/stoichiometry.html
                    Answered by
            Neha
            
    8.75/34.02 (molar mass of H2O2) = .257 mol H2O2
Since the mol ratio b/t H2O2 and O2 is 1:1, there is also .257 mol O2
.257 mol * 6.02 * 10^23 = 1.55 * 10^24 molecules so the 3rd option.
    
Since the mol ratio b/t H2O2 and O2 is 1:1, there is also .257 mol O2
.257 mol * 6.02 * 10^23 = 1.55 * 10^24 molecules so the 3rd option.
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