Asked by mike
A car traveling 95 km/h slows down at a constant 0.80 m/s^2 just by "letting up on the gas.
A) Calculate the distance it travels during the second second.
B) Calculate the distance it travels during ninth second.
A) Calculate the distance it travels during the second second.
B) Calculate the distance it travels during ninth second.
Answers
Answered by
bobpursley
convert km/h to m/s
d=Vi*t-1/2 a t^2
find the distance the first second,then find the distance at t=2. Subtract.
Do the same for the t=10, and t=9. Subtract.
d=Vi*t-1/2 a t^2
find the distance the first second,then find the distance at t=2. Subtract.
Do the same for the t=10, and t=9. Subtract.
Answered by
mike
thank you!
Answered by
Gavin
Do the same for the t=9, and t=8. Subtract.
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