Given the following sets, select the statement below that is true.
A = {l, a, t, e, r}, B = {l, a, t, e},
C = {t, a, l, e}, D = {e, a, t}
5 answers
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Sorry about that....
Given the following sets, select the statement below that is true.
A = {l, a, t, e, r}, B = {l, a, t, e}, C = {t, a, l, e}, D = {e, a, t}
B ⊂ C and C ⊆ A
C ⊆ B and D ⊂ B
D ⊂ A and A ⊂ D
B ⊂ A and C ⊂ D
D ⊆ A and A ⊂ C
Given the following sets, select the statement below that is true.
A = {l, a, t, e, r}, B = {l, a, t, e}, C = {t, a, l, e}, D = {e, a, t}
B ⊂ C and C ⊆ A
C ⊆ B and D ⊂ B
D ⊂ A and A ⊂ D
B ⊂ A and C ⊂ D
D ⊆ A and A ⊂ C
⊂ means "a proper subset of"
P ⊂ Q requires that every element of P is also in element Q, and in addition, P cannot be equal to Q.
⊆ means "a subset of, or equal to"
Based on the given information, give an attempt at the solution.
P ⊂ Q requires that every element of P is also in element Q, and in addition, P cannot be equal to Q.
⊆ means "a subset of, or equal to"
Based on the given information, give an attempt at the solution.
my answer would be C ⊆ B and D ⊂ B...is that correct?
Your answer is correct.
C={t,a,l,e}
B={l,a,t,e}
Since they contain exactly the same elements, we cannot say C⊂B, nor B⊂C, but C⊆B or B⊆C would both be correct.
Also, since
D = {e, a, t}
every element of D is in C, while the element "l" that is in C but not n D.
We can therefore safely say that D is a proper subset of C.
C={t,a,l,e}
B={l,a,t,e}
Since they contain exactly the same elements, we cannot say C⊂B, nor B⊂C, but C⊆B or B⊆C would both be correct.
Also, since
D = {e, a, t}
every element of D is in C, while the element "l" that is in C but not n D.
We can therefore safely say that D is a proper subset of C.