Question
A penguin sliding on ice has an initial velocity of 5 m/s due north. Due to a strong wind, the penguin has an acceleration of 2 m/s2 SE. What is the penguin’s displacement (magnitude and direction) after 4 seconds
Answers
Henry
SE = -45 deg. = 315 deg CCW.
a(v) = 2sin315 = -1.414m/s^2. = ver.
component of acceleration.
D = Vo*t + 0.5at^2,
D = 5*4 + 0.5*(-1.414)*4^2,
D = 20 - 11.3 = 9.7m. Due North.
a(v) = 2sin315 = -1.414m/s^2. = ver.
component of acceleration.
D = Vo*t + 0.5at^2,
D = 5*4 + 0.5*(-1.414)*4^2,
D = 20 - 11.3 = 9.7m. Due North.