Asked by Hillary
if [OH<sup>-</sup>]=10<sup>-pOH</sup>. NAd the pOH=7.85 then what does [OH<sup>-</sup>]equal?
Answers
Answered by
DrBob222
pOH = 7.85
- log(OH^-) = 7.85
(OH^-) = 1.41 x 10^-8
Do you know how to do this on your calculator. Enter 7.85 on the calculator, hit the change sign (or if your calculator doesn't have a changr sign, enter -7.85), then hit the 10<sup>x</sup> button.
- log(OH^-) = 7.85
(OH^-) = 1.41 x 10^-8
Do you know how to do this on your calculator. Enter 7.85 on the calculator, hit the change sign (or if your calculator doesn't have a changr sign, enter -7.85), then hit the 10<sup>x</sup> button.
Answered by
Hillary
thank you so much
you simplified it for me perfectly.
you simplified it for me perfectly.
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