Asked by Ms.Ellis
solving using the solution method.
x+10y=41
x+9y=37
=
x+10y=41
x+9y=37
=
Answers
Answered by
Henry
I assume you mean the substitution method:
Eq1: X + 10Y = 41.
Eq2: X + 9Y = 37.
Multiply both sides of Eq1 by -1 and
add the 2 Eqs:
-X - 10Y = -41.
X + 9Y = 37.
Sum: 0 - Y = -4,
Y = 4.
In Eq2, substitute 4 for Y:
X + 9*4 = 37,
X = 37 - 36 = 1.
Solution Set = (X,Y) = (1,4).
Eq1: X + 10Y = 41.
Eq2: X + 9Y = 37.
Multiply both sides of Eq1 by -1 and
add the 2 Eqs:
-X - 10Y = -41.
X + 9Y = 37.
Sum: 0 - Y = -4,
Y = 4.
In Eq2, substitute 4 for Y:
X + 9*4 = 37,
X = 37 - 36 = 1.
Solution Set = (X,Y) = (1,4).
Answered by
Henry
Substitution Method:
Eq1: X + 10Y = 41.
Eq2: X + 9Y = 37.
In Eq1, solve for X and get:
X = -10Y + 41,
In Eq2,substitute -10Y + 41 for X:
(-10Y+41) + 9Y = 37,
-Y = 37 - 41 = -4,
Y = 4.
In Eq1, substitute 4 for Y:
X + 9*4 = 37,
X = 37 - 36 = 1.
Solution Set = (X,Y) = (1,4).
Eq1: X + 10Y = 41.
Eq2: X + 9Y = 37.
In Eq1, solve for X and get:
X = -10Y + 41,
In Eq2,substitute -10Y + 41 for X:
(-10Y+41) + 9Y = 37,
-Y = 37 - 41 = -4,
Y = 4.
In Eq1, substitute 4 for Y:
X + 9*4 = 37,
X = 37 - 36 = 1.
Solution Set = (X,Y) = (1,4).
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