You need to learn this quickly: this is NOT precalculus, but at best ordinary Alg II.
when x=-8, y is a minimum, so x=-8 must be at the vertex. When x=-8, y=-9, so (-8,-9) is the vertex.
Give the coordinates of the vertex and graph the equation in a window that includes the vertex. y=(x+8)²-9.
I know how to graph just not how to do the problem. HELP!
4 answers
Find the exact solutions to the quadratic equation in the complex numbers.
(x-13)²=-36
(x-13)²=-36
Kevin Smith I have answered that question three times for you already.
Posted by Kevin Smith on Friday, July 1, 2011 at 2:38pm.
Find the exact solutions to the quadratic equation in the complex numbers.
(x-13)²=-36
algebra - Damon, Friday, July 1, 2011 at 5:35pm
x - 13 = + sqrt (-36)
x = 13 + 6 i
or
x-13 = - sqrt (-36)
x = 13 - 6 i
Note that those two solutions are complex conjugates.
Find the exact solutions to the quadratic equation in the complex numbers.
(x-13)²=-36
algebra - Damon, Friday, July 1, 2011 at 5:35pm
x - 13 = + sqrt (-36)
x = 13 + 6 i
or
x-13 = - sqrt (-36)
x = 13 - 6 i
Note that those two solutions are complex conjugates.
1 answer