The following reaction:
2SO3 (g) ! 2SO2 (g) + O2 (g) has an equilibrium constant equal to 0.23 M. If the following concentrations are present:
[SO2] =0.480 M, [O2] = 0.561 M, [SO3] = 0.220 M, is the reaction at equilibrium? If not, which way must it shift to reach equilibrium?
2 answers
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Find the reaction quotient or Q.
Q = (SO2)^2 x (O2)/(SO3)^2
Q = (0.480)^2(0.561)/(0.220)^2
Q = 2.67
Compare this to K = 0.23 in the problem.
Q is to high meaning SO2 and O2 are too high and SO3 is too low; therefore, it much shift to the left to reach equilibrium. That way SO2 and O2 are lowered and SO3 is raised.
Q = (SO2)^2 x (O2)/(SO3)^2
Q = (0.480)^2(0.561)/(0.220)^2
Q = 2.67
Compare this to K = 0.23 in the problem.
Q is to high meaning SO2 and O2 are too high and SO3 is too low; therefore, it much shift to the left to reach equilibrium. That way SO2 and O2 are lowered and SO3 is raised.
1 answer