If a person weighs 160 pounds, and the surface area of the bottom of both feet combined is 200 cm2. What is the pressure under the person’s feet (unit: N/m2)? What is the pressure if the person stands on only one foot (unit: N/m2)? [Hint: 1 kg = 2.2 lbs, 1 cm = 0.01 m, 1 cm2 = 0.0001 m2]

asked by Anonymous

14 years ago

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1 answer

pressurebothfeet=W/area=160*1kg/2.2lbs /(.0001*200)

compute that.

answered by bobpursley

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Question

If a person weighs 160 pounds, and the surface area of the bottom of both feet combined is 200 cm2. What is the pressure under the person’s feet (unit: N/m2)? What is the pressure if the person stands on only one foot (unit: N/m2)? [Hint: 1 kg = 2.2 lbs, 1 cm = 0.01 m, 1 cm2 = 0.0001 m2]

1 answer

pressurebothfeet=W/area=160*1kg/2.2lbs /(.0001*200)

compute that.

bobpursley · Answer

pressurebothfeet=W/area=160*1kg/2.2lbs /(.0001*200) compute that.