Asked by Mia
Solve.
(3^2x)+5=(9^2x-5)
(3^2x)+5=(9^2x-5)
Answers
Answered by
MathMate
Hint:
(3^2x)+5=(9^2x-5)
Rewrite as
(3^2x)+5 = (3^2x)²-5
Set y=3^2x
y²-y-10=0
Solve for y and backsubstitute to solve for x.
I get x=0.6 approx.
(3^2x)+5=(9^2x-5)
Rewrite as
(3^2x)+5 = (3^2x)²-5
Set y=3^2x
y²-y-10=0
Solve for y and backsubstitute to solve for x.
I get x=0.6 approx.
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