Asked by Josh

Hey, it's me again,

Can someone help me with this question?

A water balloon is dropped from the top of a building. Assume the balloon does not break when it strikes the ground. If the water balloon falls a distance of 21m, what is the maximum temperature rise of the water balloon due to it being dropped?

I'm not sure where to begin!
Answered by drwls
The potential energy becomes heat, Q.
Use the heat to compute the temperature rise.

Delta T = Q/(M*C) = (1/2)M g H/(M*C)
= (1/2)g H/C
C is the water specific heat, 4180 joules/kg C
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