Asked by Lance

Assume the heat absorbed by the calorimeter was 200J. What is the calorimeter constant (Heat Capacity) if the temperature changed from 22C to 26C?
I know the answer is 50 J/k. But I am not sure how to get this.
Answered by DrBob222
q = Qcal x delta T
200 = Qcal x 4
Answered by Lance
Thank you!
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