Asked by Maddy
How would I solve:
X^(4/3)+X^(2/3)=28
X^(4/3)+X^(2/3)=28
Answers
Answered by
Bosnian
In google type:
wolfram alpha
When you see list of results click on:
Wolfram Alpha:Computational Knowledge Engine
When page be open in rectangle type:
solve x^(4/3)+x^(2/3)=28
and click option =
After few seconds you will see solution.
Then click option:
Show steps
wolfram alpha
When you see list of results click on:
Wolfram Alpha:Computational Knowledge Engine
When page be open in rectangle type:
solve x^(4/3)+x^(2/3)=28
and click option =
After few seconds you will see solution.
Then click option:
Show steps
Answered by
Reiny
let x^(2/3) = y
then we have
y^2 + y - 28 = 0
y = (-1 ± √113)/2
so x^(2/3) = (1+√113)/2
x = [(1 + √113)/2]^(3/2) = appr. 10.566
or x^(2/3) = (-1 - √113)/2 , which has no solution
then we have
y^2 + y - 28 = 0
y = (-1 ± √113)/2
so x^(2/3) = (1+√113)/2
x = [(1 + √113)/2]^(3/2) = appr. 10.566
or x^(2/3) = (-1 - √113)/2 , which has no solution
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