Asked by Anonymous
If it requires 30.0 milliliters of 1.2 molar HCl to neutralize 20.0 milliliters of NaOH, what is the concentration of the NaOH solution?
Balanced equation: NaOH + HCl NaCl + H2O (3 points)
Balanced equation: NaOH + HCl NaCl + H2O (3 points)
Answers
Answered by
DrBob222
You need to learn to place an arrow; otherwise, we don't know the difference between the reactants and the products. In this case, how many mole HCl did you use? mole HCl = M x L = ??
Now convert, using the coefficients in the balanced equation, to moles NaOH. The equation is a 1:1 ratio of HCl to NaOH; therefore, moles HCl = moles NaOH.
Then M NaOH = moles NaOH/L NaOH.
Now convert, using the coefficients in the balanced equation, to moles NaOH. The equation is a 1:1 ratio of HCl to NaOH; therefore, moles HCl = moles NaOH.
Then M NaOH = moles NaOH/L NaOH.
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