Asked by RANDA

Given the quadratic function f(x) = x2 – 12x + 36, find a value of x such that f(x) = 25.
Answered by MathMate
Given f(x) = x2 – 12x + 36
and f(x)=25, equate:
25 = x² - 12x + 36
x&sup2-12x+11=0
(x-11)(x-1)=0
therefore x=11 or x=1