Asked by Khalid
Sum of 2 numbers is 1 and their product is 1/8. Find their difference.
Answers
Answered by
bobpursley
a+b=1
ab=1/8 or b=1/8a
a+1/8a=1
8a^2 -8a+1=0
a^2-a+1/8=0
a=(1+-sqrt(1-1/2))/2
a=(1/2 +-sqrt(1/8)
if a= 1/2 + sqrt(1/8), then b must be 1/2 -sqrt (1/8)
ab=1/8 or b=1/8a
a+1/8a=1
8a^2 -8a+1=0
a^2-a+1/8=0
a=(1+-sqrt(1-1/2))/2
a=(1/2 +-sqrt(1/8)
if a= 1/2 + sqrt(1/8), then b must be 1/2 -sqrt (1/8)
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