Asked by Anonymous
An object with 15 grams mass is immersed in benzene and suffers an apparent loss of mass 5g What is the approximate specific gravity of the object? (specific gravity of benzene = 0.7)
Answers
Answered by
Damon
volume of object * .7 g/cm^3 = 5 g
so
V = 5/.7 = 7.14 cm^3
density = 15/7.14 = 2.1 g/cm^3
or specific gravity of 2.1 times water
so
V = 5/.7 = 7.14 cm^3
density = 15/7.14 = 2.1 g/cm^3
or specific gravity of 2.1 times water
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