Asked by Brea
Use the following balanced equation.
3Sr(OH)2 + 2H3PO4 --> 6H20 + Sr3(PO4)2
How many grams of Sr3(PO4)2 could be produced by the complete reaction of 200 mL of 0.40 M H3PO4?
3Sr(OH)2 + 2H3PO4 --> 6H20 + Sr3(PO4)2
How many grams of Sr3(PO4)2 could be produced by the complete reaction of 200 mL of 0.40 M H3PO4?
Answers
Answered by
DrBob222
See your other post below.
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