Since the Z and T score are standard for any normal distribution, you don't even need to know the mean or standard deviation of that distribution to answer your questions.
Z score = standard deviations away from the mean.
T score = 50 + 10Z
On a test whose distribution is approximately normal with a mean of 50 and a standard deviation of 10, the results for three students were reported as follows:
Student Opie has a T-score of 60.
Student Paul has a z-score of -1.00.
Student Quincy has a z-score of +2.00.
Obtain the z-score and T-score for EACH student. Show your calculations. Who did better on the test? How many standard deviation units is each score from the mean? Compare the results of the three students.
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