Asked by kavita
In the given diagram,AB represents a vertical pole and CD represents a 40 m high tower both of which are standing on the same horizontal plane.From the top of the tower,the angles of depression of the top and the foot of the pole are 24 degrees,30 inches and 48 degrees,30 inches respectively.calculate
(i) the horizontal distance between the pole and the tower
(ii) the height of the pole
(i) the horizontal distance between the pole and the tower
(ii) the height of the pole
Answers
Answered by
Reiny
Tough to figure out from the "non-given" diagram.
let DB, the horizontal distance be x.
angle ADB = 48 degrees, 30 minutes (not inches!)
= 48.5°
so tan 48.5 = 40/x
x = 40/tan48.5 = 35.39 m
from C, draw a horizontal to meet AB at E
tan 24.5 = AE/x
AE = xtan24.5 = 16.13 m
so height of pole = BE = 40-16.128 = 23.87 m
let DB, the horizontal distance be x.
angle ADB = 48 degrees, 30 minutes (not inches!)
= 48.5°
so tan 48.5 = 40/x
x = 40/tan48.5 = 35.39 m
from C, draw a horizontal to meet AB at E
tan 24.5 = AE/x
AE = xtan24.5 = 16.13 m
so height of pole = BE = 40-16.128 = 23.87 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.