Asked by Brittani
Solve the systems using substitution.
1.6x + 2y = -2
4x + y = 1
1.6x + 2y = -2
4x + y = 1
Answers
Answered by
Henry
Eq1: 1.6X + 2Y = -2.
Eq2: 4x + y = 1.
Solve for y in Eq1:
4X + Y = 1,
Y = -4X + 1.
Substitute -4X+1 for Y in Eq1:
1.6X + 2(-4X + 1) = -2,
1.6X -8X + 2 = -2,
-6.4X = -4,
X = 0.625.
In Eq2, substitute 0.625 for X:
4*0.625 + Y = 1,
2.5 + Y = 1,
Y = 1 - 2.5 = -1.5.
Solution set = (X,Y) = (0.625,-1.5).
Eq2: 4x + y = 1.
Solve for y in Eq1:
4X + Y = 1,
Y = -4X + 1.
Substitute -4X+1 for Y in Eq1:
1.6X + 2(-4X + 1) = -2,
1.6X -8X + 2 = -2,
-6.4X = -4,
X = 0.625.
In Eq2, substitute 0.625 for X:
4*0.625 + Y = 1,
2.5 + Y = 1,
Y = 1 - 2.5 = -1.5.
Solution set = (X,Y) = (0.625,-1.5).