Asked by Anonymous
evaluate dx/8+2x^2
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Answered by
MathMate
∫dx/(8+2x^2)
=(1/4)∫(1/2)dx/(1+(x/2)^2)
use y=(x/2), dy=dx/2
=(1/4)∫dy/(1+y²)
=(1/4)atan(y)+C
=(1/4)atan(x/2)+C
=(1/4)∫(1/2)dx/(1+(x/2)^2)
use y=(x/2), dy=dx/2
=(1/4)∫dy/(1+y²)
=(1/4)atan(y)+C
=(1/4)atan(x/2)+C
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