Asked by Dexter

Please help me verify the following question:
Consider the following ion; XF2-2
What is the oxidation number assigned to element “X”? Show your work

My answer:
X F2-2
X -1(-1)
X -3=0
X = +3

Please let me know if right. Many thanks!
Answered by DrBob222
Nope. If X = 3, then XF2^2- would be +3 for X, -2 for two F, so the charge would be +1. Try X = 0. Each F is -1 for a total F of -2. Then 0 for X + (-2) for F leaves a charge of -2 on the ion which it has.
Answered by Dexter
Having it explained that way makes it easier to understand and helps to verify answer in the end which my course didn't explain. Thank you.
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