I know how to "due" the equation also,and here it is.
y=mx+b
put in the y,x, knowing m
-8=4/5 *7 + b solve for b.
-8=28/5+b
-40=28+5b
5b=-68
b=-68/5
y=4/5 x -68/5
I have no idea what your work is, it makes no sense to me.
Find an equation of the line having the given slope and containing the given point.
M=4/5, (7,-8)
I can totally due the equation
y+8=4/5x-28/5
but keep getting the answer wrong. I cannot figure out how subtracting 8 they get the answer
y=4/5x-68/5
PLEASE HELP!
4 answers
In your work, you forgot the brackets
it should be
y+8 = (4/5)(x-7)
now multiply by 5 to get rid of fractions
5y + 40 = 4x - 28
4x - 5y = 68
rearrange to get the same answer as bobpursley gave you
it should be
y+8 = (4/5)(x-7)
now multiply by 5 to get rid of fractions
5y + 40 = 4x - 28
4x - 5y = 68
rearrange to get the same answer as bobpursley gave you
the formula I'm suppose to be using is y-y1=m(x-x1)
m=4/5 (7,-8)
I don't understand your answer
m=4/5 (7,-8)
I don't understand your answer
that is exactly the formula I used for you
y - y1 = m(x - x1)
y -8 = (4/5)(x-7)
I then described what I did next
4x - 5y = 68
-5y = -4x + 68
divided everybody by -5
y = (4/5)x - 68/5
y - y1 = m(x - x1)
y -8 = (4/5)(x-7)
I then described what I did next
4x - 5y = 68
-5y = -4x + 68
divided everybody by -5
y = (4/5)x - 68/5
1 answer