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find the surface area obtained by revolving about the line y =1 the region enclosed by the curve x= 3/5y5/3 -3/4y1/3 on [0,1]
14 years ago

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find the surface area obtained by revolving about the line y =1 the region enclosed by the curve x= 3/5y5/3 -3/4y1/3 on [0,1]

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