Asked by June
Suppose, in the figure below, a 0.90-m rod experiences a 1.2-T magnetic field and the hand keeps it moving to the right at a constant speed of 3.5 m/s. If the current in the circuit is 0.040 A, what is the average power being delivered to the circuit by the hand?
Answers
Answered by
drwls
There is no "figure below".
Average power is the force on the bar multiplied by the velocity.
The force on the bar is B*I*L
L = 0.90 m
B = 1.2 Tesla
I = 0.040 A
Average power is the force on the bar multiplied by the velocity.
The force on the bar is B*I*L
L = 0.90 m
B = 1.2 Tesla
I = 0.040 A
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