Asked by John

The solubility product of copper(II) iodate, Cu(IO3)2, is 4 x 10-9 mol3 dm-9 at 25 °C.
What is the solubility of copper(II) iodate in g dm-3?



A 1.85 × 10-2
B 4.14 × 10-1
C 5.21 × 10-1
D 6.56 × 10

Answers

Answered by John
Also please i'd really appreciate if someone could explain me also how to do it.. like from step 1 to end ~

Thanks.. @@..
Answered by DrBob222
Cu(IO3)2 ==> Cu^2+ + 2IO3^-

Ksp = (Cu^2+)(IO3^-)^2
Make and ICE chart and substitute into Ksp expression.
(Cu^2+) = x
(IO3^-) = 2x
Solve for x, which will be in M, and multiply by molar mass to find grams.
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