Asked by Alex
HELP!
Two Chords AB and CD, are equidistant from the center of a circle. AB=3x+7 and CD=27-x. Solve for x and find the lengths of AB and CD
Two Chords AB and CD, are equidistant from the center of a circle. AB=3x+7 and CD=27-x. Solve for x and find the lengths of AB and CD
Answers
Answered by
Reiny
If they are equidistant, the clearly they must be equal
so solve
3x + 7 = 27-x
4x = 20
x = 5
AB = 3(5)+7 = 22
CD = 22
so solve
3x + 7 = 27-x
4x = 20
x = 5
AB = 3(5)+7 = 22
CD = 22