Asked by Alex
                HELP!
Two Chords AB and CD, are equidistant from the center of a circle. AB=3x+7 and CD=27-x. Solve for x and find the lengths of AB and CD
            
        Two Chords AB and CD, are equidistant from the center of a circle. AB=3x+7 and CD=27-x. Solve for x and find the lengths of AB and CD
Answers
                    Answered by
            Reiny
            
    If they are equidistant, the clearly they must be equal
so solve
3x + 7 = 27-x
4x = 20
x = 5
AB = 3(5)+7 = 22
CD = 22
    
so solve
3x + 7 = 27-x
4x = 20
x = 5
AB = 3(5)+7 = 22
CD = 22
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