Asked by ChemLover

Is the following reaction spontaneous at 25*C?
delta s reaction = -217 J/K*mol
delta H rxn = -1202 KJ

2Mg (s) + O2 (g) -> 2MgO (s)

delta suniverse = delta s system - delta H system / T

i got positive (+) 3.81 x 10 ^ 3 J/K

and my notes says it is spontaneous but i feel like it is non spontaneous

because when delta g is negative and delta h is < tdeltas it should be spontaneous & the opposite of that makes it non spon for an endothermic reaction....i hope this makes sense


my question is why is it spontaneous? thank you in advance

Answers

Answered by DrBob222
I'm having trouble making sense of it. If DS for the reaction = -217 J/K then why do you have it listed as -217 J/K*mol? So is DS rxn = -217 J or 2*-217 J?
Same kind of question for DH.
Answered by ChemLover
DS = -217 J/(K)mol
DH = -1202 KJ -> -1202 x 10^3 J

does this make any sense?
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