Asked by Liz
                A car passes by a certain point at time t = 0 hours heading east at 40 miles per hour. At t = 1 hour another car passes by the same point heading north at 50 miles per hour. What is the functiuonthat equals the distance between the two cars? 
            
            
        Answers
                    Answered by
            bobpursley
            
    distance= sqrt[(40t)^2+(50(t-1))^2 ]
check my thinking.
    
check my thinking.
                    Answered by
            Liz
            
    The answer has to be one of the following:
a. L=90t-50
b. L= sqrt(4100t)
c. L= sqrt(4100t^2 +5000t +2500)
d. L= sqrt(4100t^2-5000t + 2500)
e. L= sqrt(90t-50)
    
a. L=90t-50
b. L= sqrt(4100t)
c. L= sqrt(4100t^2 +5000t +2500)
d. L= sqrt(4100t^2-5000t + 2500)
e. L= sqrt(90t-50)
                    Answered by
            bobpursley
            
    And, it is one of those.  Can you not do the algebra?
    
                    Answered by
            Anonymous
            
    just simplify what bob put you'll get D!
    
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