Asked by Vinny
Determine how many grams of active antacid ingredient AL(OH)3 would be necessary to neutralize the HCL in 50.0 mL of .0100 M HCL (an approximation of the conc. of HCL in the stomach)
3HCL9aq)+AL(OH)3(s)-> AlCL3 (aq) = 3H2O (L)
3HCL9aq)+AL(OH)3(s)-> AlCL3 (aq) = 3H2O (L)
Answers
Answered by
bobpursley
stop it. YOu are posting questions with no work, looking for someone to do your thinking and work for you.
Answered by
th
20
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