Question

Evaluate (if possible) the sine,cosine, and tangent of the angle

10pi/3

Answer 1

10π/3 - 2π = 3π/2

then see

http://www.jiskha.com/display.cgi?id=1307390418

Answer 2

(10pi/3)rad * (1/2pi)rev/rad = 5/3 =
1 2/3 rev.
2/3 rev * 360deg/rev = 240 deg.

sin(240) = -0.8660 = -(sqrt3)/2.

cos(240) = -0.50 = -1/2.

tan(240) = 1.732 = sqrt3.

240 deg. = 4pi/3 rad.