Asked by rosemary flores
solve the triangle a=1 b=2 C=50 degrees
Answers
Answered by
Reiny
guessing that you are describing a triangle ABC , use the cosine law
c^2 = a^2 + b^2 - 2(a)(b)cosC
= 1 + 4 - 2(1)(2)cos50
= 2.42885
c = 1.5585
Now use the sine law to find a second angle.
The use the angle sum of a triangle to find the third angle.
c^2 = a^2 + b^2 - 2(a)(b)cosC
= 1 + 4 - 2(1)(2)cos50
= 2.42885
c = 1.5585
Now use the sine law to find a second angle.
The use the angle sum of a triangle to find the third angle.
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