Consider the following.
newskills15
Solve for BC (the the nearest hundredth).
Consider the following.
f\(x\) = 5tan(1/3 x + pi/2)
The period of the function above is ...
3 answers
5tan((1/3)x + π/2)
= 5tan [(1/3)(x + 3π/2)]
period = 2π/(1/3) = 6π
= 5tan [(1/3)(x + 3π/2)]
period = 2π/(1/3) = 6π
onsider the following.
newskills15
Solve for BC (the the nearest hundredth).
newskills15
Solve for BC (the the nearest hundredth).
1 answer