Asked by Robo
Find the value of c such that the point (4,2) lies in the graph of f(x)= cx^2+3x-4.
Answers
Answered by
Henry
F(x) = CX^2 + 3X - 4.
Xv = -b/2a = -3 / 2c = 4,
-3 / 2c = 4,
c = -3/8.
Xv = -b/2a = -3 / 2c = 4,
-3 / 2c = 4,
c = -3/8.
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