Question
Write the expression below as a single logarithm. Please show all of your work.
ln((x^2 – 1)/(x^2 – 6x + 8)) – ln((x+1)/(x+2))
ln((x^2 – 1)/(x^2 – 6x + 8)) – ln((x+1)/(x+2))
Answers
Damon
ln((x^2 – 1)/(x^2 – 6x + 8)) – ln((x+1)/(x+2))
when you subtract the logs, you divide the arguments
ln (x+1)(x-1) / [(x+1)(x-1)((x-4)(x-2)]
ln 1/[(x-4)(x-2)]
ln [ (x-4)(x-2) ]^-1
-ln [ (x-4)(x-2)]
when you subtract the logs, you divide the arguments
ln (x+1)(x-1) / [(x+1)(x-1)((x-4)(x-2)]
ln 1/[(x-4)(x-2)]
ln [ (x-4)(x-2) ]^-1
-ln [ (x-4)(x-2)]
Anonymous
6logb v+2logb t
Bob
12logb^2vt