Asked by math...
ABCD is a rectangle, in which BC=2AB. A point E lies on ray CD, such that CE=2BC. Prove that BE perpendicular AC.
Answers
Answered by
Reiny
let AB = x
then BC = 2x
CE = 2(2x) = 4x
slope BE = 4x/(2x) = 2
slope AC = -x/(2x) , negative since it leans to the left
= -1/2
since 2 is the negative reciprocal of -1/2,
BE and AC are perpendicular.
or
place rectangle ABCD on the x-y grid with B at the origin.
A is (0,x)
B is (,0)
C is (2x, 0)
D is (2x, x)
E is (2x, 4x)
find slope BE and slope AC to show the same result
then BC = 2x
CE = 2(2x) = 4x
slope BE = 4x/(2x) = 2
slope AC = -x/(2x) , negative since it leans to the left
= -1/2
since 2 is the negative reciprocal of -1/2,
BE and AC are perpendicular.
or
place rectangle ABCD on the x-y grid with B at the origin.
A is (0,x)
B is (,0)
C is (2x, 0)
D is (2x, x)
E is (2x, 4x)
find slope BE and slope AC to show the same result
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