Asked by Michael

A 1.5 uF capacitor is connected to a 9.0 V battery. Use PE=1/2C(change in V)^2 to find the energy stored in the capacitor.
Answered by drwls
C = 1.5*10^-6 farads
V = 9.0 volts

You have the formula. Do the calculation.

The answer, (1/2)CV^2, will be in joules
Answered by Anonymous
0.000018
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