Asked by rodrigo
Let f(x)= -3x^4+79x^2-3x+1/ 5x^4+19x^3+2x+5. Discuss the short run behavior for f(x) and the long run behavior for f(x).
Answers
Answered by
Reiny
The way you type these questions without brackets, it is difficult to determine what the denominator is, as other tutors have also noted.
I will assume that 5x^4+19x^3+2x+5 is your denominator.
To check for vertical asymptotes, I set this equal to zero.
First of all I could not factor it, so I went to a reliable "equation solver".
http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=equations&s2=solve&s3=basic
gave me two complex and two real solutions.
so there are two veritical asymptotes, one around x = -3.8, another around x = -.62
when x=0 your function has value 1/5, so the y-intercept is 1/5
setting the numerator equal to zero in the same program gave me 2 real and 2 complex solutions
the reals at x=-5.15 and x=5.11
so the graph crosses the x-axis at those values
as x approaches ±infinity, your function approaches y=-3/5
(Are you supposed solve these with the use of a programmable calculator?
They seem rather unreasonable to work with otherwise)
I will assume that 5x^4+19x^3+2x+5 is your denominator.
To check for vertical asymptotes, I set this equal to zero.
First of all I could not factor it, so I went to a reliable "equation solver".
http://www.hostsrv.com/webmab/app1/MSP/quickmath/02/pageGenerate?site=quickmath&s1=equations&s2=solve&s3=basic
gave me two complex and two real solutions.
so there are two veritical asymptotes, one around x = -3.8, another around x = -.62
when x=0 your function has value 1/5, so the y-intercept is 1/5
setting the numerator equal to zero in the same program gave me 2 real and 2 complex solutions
the reals at x=-5.15 and x=5.11
so the graph crosses the x-axis at those values
as x approaches ±infinity, your function approaches y=-3/5
(Are you supposed solve these with the use of a programmable calculator?
They seem rather unreasonable to work with otherwise)
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