Asked by mema
rewrite as an equivalent loganthmic
e-^2=0.1353
e-^2=0.1353
Answers
Answered by
MathMate
Given:
e^(-2)=0.1353
Take (natural) log on both sides:
log(e^(-2))=log(0.1353) ...(1)
Since log(base n)n^x = x
then log<sub>e</sub>e^x = x
We rewrite the previous expression (1) as
-2 = log<sub>e</sub>(0.1353)
or
log<sub>e</sub>(0.1353) = -2
e^(-2)=0.1353
Take (natural) log on both sides:
log(e^(-2))=log(0.1353) ...(1)
Since log(base n)n^x = x
then log<sub>e</sub>e^x = x
We rewrite the previous expression (1) as
-2 = log<sub>e</sub>(0.1353)
or
log<sub>e</sub>(0.1353) = -2
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