Asked by Lsat
Find all solutions of the equation on the interval [0,2pi):
Tan^2x=1-secx
Tan^2x=1-secx
Answers
Answered by
Bosnian
In google type:
wolfram alpha
When you see lis of results click on:
Wolfram Alpha:Computational Knowledge Engine
When page be open in rectangle type:
solve tan^2(x)=1-sec(x)
and click option =
After few secons you will see result.
Then clic option Show steps
wolfram alpha
When you see lis of results click on:
Wolfram Alpha:Computational Knowledge Engine
When page be open in rectangle type:
solve tan^2(x)=1-sec(x)
and click option =
After few secons you will see result.
Then clic option Show steps
Answered by
Bosnian
Remark:
When you see step
Simplify trigonometric functions:
If we know that:
tan^2(x)=sec^2(x)-1
tan^2(x)+sec^2(x)-1=0 becomes:
sec^2(x)-1+sec(x)-1=0
When you see step
Simplify trigonometric functions:
If we know that:
tan^2(x)=sec^2(x)-1
tan^2(x)+sec^2(x)-1=0 becomes:
sec^2(x)-1+sec(x)-1=0
Answered by
Reiny
sec^2 x - 1= 1 - secx
sec^2 x + sec x - 2 = 0
(secx + 2)(secx -1) = 0
secx = -2 or secx = 1
cosx = -1/2 or cosx = 1
x = 120° or x = 240° or x = 0 or x = 360°
x = 0, 2π/3 , 4π/3, 2π
sec^2 x + sec x - 2 = 0
(secx + 2)(secx -1) = 0
secx = -2 or secx = 1
cosx = -1/2 or cosx = 1
x = 120° or x = 240° or x = 0 or x = 360°
x = 0, 2π/3 , 4π/3, 2π
Answered by
Lsat
Thank you!
Answered by
shieda
find all solutions to the equation 2x^3+12x^2+50x=0
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