Asked by Paul
A chemistry teacher needs 2.5 liters of a sulfuric acid solution that is 20% sulfuric acid and 80% water . He has 2 liters of a 15% sulfuric acid solutionleft over from earlier laboratory exercises. He also has 44 liters of a 50% solution. Let x represent the number of liters of the 15% solution that can be mixed with Y liters of the 50% solution to make 2.5 liters of the needed 20% solution. Which of the following shows a system of equations that could get the solved to find the amounts of the 15% and 50% solutions that could be mixed to get the required solution?
A) X+Y=2.5
0.15X+0.50Y=0.20
B) x+y=0.20(2.5)
0.15x+0.50y=2.5
C) x+y=2.5
0.15x+0.50y=0.20(2.5)
D)x+y=0.65
x+y=0.20(2.5)
A) X+Y=2.5
0.15X+0.50Y=0.20
B) x+y=0.20(2.5)
0.15x+0.50y=2.5
C) x+y=2.5
0.15x+0.50y=0.20(2.5)
D)x+y=0.65
x+y=0.20(2.5)
Answers
Answered by
MathMate
Please check if division signs are missing in some of the answers.
What is your choice, and why?
What is your choice, and why?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.