Asked by Tori
determine the first 4 terms of the sequence tn=-n^2+7
Answers
Answered by
MathMate
t(n)=-n^2+7
for n=1
t(1)=-(1)^2+7=-1+7=6
t(2)=-(2)^2+7=-4+7=3
...
I'll leave the other two to you for practice.
for n=1
t(1)=-(1)^2+7=-1+7=6
t(2)=-(2)^2+7=-4+7=3
...
I'll leave the other two to you for practice.
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