Asked by Eric
A square and four congruent rectangles are arranged in a larger square. The smaller square and each of the rectangles have the same perimeter.Determine the ratio of the length of a side of the larger square to the length of side of the smaller square.
Answers
Answered by
Mgraph
Let A is the length of a side of the larger square, a - of the smaller square.
The length of the smaller side of
a rectangle is (A-a)/2, the length of
the bigger side is (A-a)/2+a.
4a=2((A-a)/2+(A-a)/2+a)
4a=2A
A/a=2/1
The length of the smaller side of
a rectangle is (A-a)/2, the length of
the bigger side is (A-a)/2+a.
4a=2((A-a)/2+(A-a)/2+a)
4a=2A
A/a=2/1
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