∫_0^(1/2)xdx/√(1-x²)
I do not know what
0^(1/2)
is. It is probably a symbol that I do not have.
Integral of x dx/sqrt(1-x^2)
let x = sin t
then dx = cos t dt
1-x^2 = 1 -sin^2 t = cos^2 t
so
integral of
sin t cos t dt / cos t
= integral of
sin t dt
=-cos t
but
-cos t = -sqrt(1-x^2)
∫_0^(1/2)xdx/√(1-x²)
1 answer