Asked by junior
definite integral
from 0 to pi/2 of cos(theta)
from 0 to pi/2 of cos(theta)
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Answered by
Anonymous
Indefinite integral cos(theta)=sin(theta)
definite integral
from 0 to pi/2 of cos(theta)=sin(pi/2)-sin(0)= 1-0 = 1
definite integral
from 0 to pi/2 of cos(theta)=sin(pi/2)-sin(0)= 1-0 = 1
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